Plans for the Week and Assignments: 1. Wednesday(11/18): Conditions for Static Equilibrium. Elasticity and the Calculation of a Modulus. HW: Read pages 362-370 and solve prob. 1, 5,11, 17, and 23 on pages 378-381. 2. Thursday(11/19): LAB on Inertial Balance. HW: Read pages 371-377 and solve prob.27, 39, and 33 on pages 381-2. 3. Friday(11/20): Post-lab Write-up. HW: Process lab data and write lab report (due Tuesday). 4. Monday(11/23): Review Ch 12 - Static Equilibrium and Elasticity. HW: Process lab data and write lab report (due Tuesday). 5. Tuesday(11/24): Click for TEST on Ch.12. HW: Go to website for notes on Ch.13 - Universal Gravitation.
Very Important: If you have any questions or miss a class, see me before school (8:00 - 8:30 AM), during Lunch, 7th hour, or after school. Best to send an email to rpersin@fau.edu.
Website Notes for Ch.12: Static Equilibrium and Elasticity. 1. Part of this chapter is concerned with the conditions under which a rigid object is in equilibrium. 2. The term equilibrium implies either that the object is at rest or that its center of mass moves with constant velocity. We deal here with the former, which are referred to as objects in static equilibrium. 3. One necessary condition for equilibrium is that the net force on an object be zero, ΣF = 0. If the object is treated as a particle, this is the onlycondition that must be satisfied for equilibrium. 4. It is also good to still know the location of the center of mass, which is the same point as the center of gravity, xcm = Σ(mi·xi)/Σmi . (Similarly for y coordinate.) 5. If the net force on the particle is zero, the particle remains at rest (if originally at rest) or moves with constant velocity (if originally in motion.) 6. The situation with real (extended) objects is more complex because objects cannot be treated as particles. 7. In order for an extended object to be in static equilibrium, the net force on it must be zero and it must have no tendency to rotate. This second condition of equilibrium requires that the net torque about any origin be zero, Στ = 0. 8. In order to establish whether or not an object is in equilibrium, we must know its size and shape, the forces acting on different parts of it, and the points of application of the various forces. 9. The last sections of this chapter deals with the realistic situation of objects that deform under load conditions. Such deformations are usually elastic in nature and do not affect the conditions of equilibrium. 10. By elastic we mean that when the deforming forces are removed, the object returns to its original shape. Several elastic constants are defined, each corresponding to a different type of deformation. 11. The elastic properties of solids are described in terms of stress and strain. Stress is a quantity that is proportional to the force causing a deformation of the object. Stress = F/A . (Same as pressure.) Strain is a measure of the degree of the resulting deformation. Strain = ΔL/Lo . 12. The elastic modulus of a material is the ratio of stress to strain for that material. There is an elastic modulus for each of the three types of deformation. 13. Young's modulus which measures resistance to change in length, is given by Y = (F/A)/(ΔL/Lo) . 14. Shear modulus which measures resistance to relative motion of the planes of a solid, is given by S = (F/A)/(Δx/h) . 15. Bulk modulus which measures the resistance to a change in volume, is given by B = (ΔF/A)/(ΔV/Vo) . View Slides Try a Quiz Try a Test And still, we need these steps to solve any problem in Physics: (i) read the problem and identify the given variables (ii) determine what you are asked to solve for (iii) find the correct vector formula to use (iv) use Algebra, Trigonometry, and/or Calculus to isolate the unknown (v) substitute-in the given information and simplify.
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